An nickel ore weighing 85.245 g was placed in a flask having a volume of 45.25 mL. The flask with the nickel ore was then filled with water and weighed. The nickel ore and the water weighed 113.571 g. The density of water is 0.9976 g/mL. Calculate the density of the nickel ore. 4. 11
Find step-by-step Chemistry solutions and your answer to the following textbook question: A sample of iron ore weighing $0.2792 mat{~g}$ was dissolved in an excess of a dilute acid solution. All the iron was first converted to $mat{Fe}$ (II) ions. The solution then required $23.30 mat{~mL}$ of $0.0194 M$ $mat{KMnO}_4$ for oxidation to …
Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed 109.3 g.
An nickel ore weighing 85.245 g was placed in a flask having a volume of 45.25 mL. The flask with the nickel ore was then filled with water and weighed. The nickel ore and the water weighed 113.571 g. The density of water is 0.9976 g / …
A sample of iron ore weighing 0.2972 g was dissolved in an excess of a dilute acid solution. All the iron was first converted to Fe(II) ions. The solution then required 24.80 mL of 0.0214 M KMnO 4 for oxidation to Fe(III) ions. Calculate the percent by mass of iron in the ore. % by mass of Fe
A sample of iron ore weighing $0.2792 mat{g}$ was dissolved in an excess of a dilute acid solution. All the iron was first converted to Fe(II) ions. The solution then required $23.30 mat{mL}$ of $0.0194 mat{M}$ KMnO_ for oxidation to Fe(III) ions. Calculate the percent by mass of iron in the ore.
Find step-by-step Chemistry solutions and your answer to the following textbook question: A sample of iron ore weighing $0.2792 mat{~g}$ was dissolved in an excess of a dilute acid solution. All the iron was first converted to $mat{Fe}$ (II) ions. The solution then required $23.30 mat{~mL}$ of $0.0194~Mmat{~KMnO}_4$ for oxidation to …
A sample of NaNO3 weighing 0.38 g is placed in a 50.0 mL volumetric flask. The flask is then filled with water to the mark on the neck. asked Oct 3, 2018 in Chemistry by Afreen ( 31.6k points)
1000 4. (EC) 70.4g of hematite (iron ore) was placed in a flask whose maximum volume was... 4) Given data is Mass of hematite (iron ore) = 70.4 g Volume of the flask = 55.0 mL The mass of hematite and water = 109.3 g The density of...
Our expert help has broken down your problem into an easy-to-learn solution you can count on. See Answer. Question: 6) Hematite (an iron ore) weighing 70.7 g was placed in a …
Solutions for Chapter 1 Problem 126GP: Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed …
(EC) 70.4g of hematite (iron ore) was placed in a flask whose maximum volume was 55.0 mL. The flask with hematite was then carefully filled with water too the maximum line and re-massed. The hematite and water had a mass of 109.3g. The density of the water was 0.996g/cm³. What was the density of the hematite?
Answer to hematite (iron ore) weighting 70.7g was placed in a. Science; Chemistry; Chemistry questions and answers; hematite (iron ore) weighting 70.7g was placed in a flask whos volume was 53.2ml. the flask with hematite was carefully filled with water and weighted the hematite and water weighted 109.3g. the density of the water was …
Click here:point_up_2:to get an answer to your question :writing_hand:a sample of nano3 weighing 038g is placed in a 500ml volumetric flask the flask. Solve. Guides. Join / Login. Use app Login. 0. You visited us 0 times! Enjoying our articles? Unlock Full Access! Standard XII. ... $$ weighing $$0.83 g$$ is placed in a $$50 ml$$ volumetric ...
Some iron wire weighing $5.6 mat{~g}$ is placed in a beaker and covered with $15.0 mat{~g}$ of dilute hydrochloric acid. ... (iron ore) weighing $70.7 mat{~g}$ …
1000 4. (EC) 70.4g of hematite (iron ore) was placed in a flask whose maximum volume was 55.0 mL. The flask with hematite was then carefully filled with water too the maximum line and re-massed. The hematite and water had a mass of 109.3g. The density of the water was 0.996g/cm³. What was the density of the hematite?
2 Hematite Iron ore weighing 707 g was placed in a flask The flask with hematite from CHM 101 at Prince Sultan University. AI Homework Help. ... Log in Join. 2 hematite iron ore weighing 707 g was placed in a. Doc Preview. Pages 4. Identified Q&As 17. Solutions available. Total views 8. Prince Sultan University. CHM. CHM 101. meow112211. 4/24 ...
Question: was the density of the quartz? 1.126 Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed The hematite and water weighed 109.3 g. The density of the water was 0.997 g/cm3. What was the density of the hematite?
A sample of iron ore weighing 0.2792 g was dissolved in dilute acid solution, and all the iron (III) was converted to iron (II) ions. The solution required 26.48 ml of 0.02315 M K2Cr2O7 (MW 294.18 g/mol) for titration. The redox reaction involved in the titration is given below. Calculate the percent by mass of iron in the ore.
A sample of iron ore weighing 0.2852 g was dissolved in an excess of a dilute acid solution. All the iron was first converted to Fe(II) ions. The solution then required 23.40 mL of 0.0204 M KMnO 4 for oxidation to Fe(III) ions. Calculate the …
Question: hematite (iron ore) weighting 70.7g was placed in a flask whos volume was 53.2ml. the flask with hematite was carefully filled with water and weighted the hematite and water weighted 109.3g. the density of the water …
Click here 👆 to get an answer to your question ️ 6 hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 ml. the flask with …
Solution For Hematite (iron ore) weighing 70.7 g was placed in a flask whose volume was 53.2 mL. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighe
VIDEO ANSWER: using the information provided. Let's calculate the density of the hematite. So we're given the mass of the hematite Is equal to 70.7 g. The mass of the hematite. Yeah. And the water Is equal to 109.3
A beaker weighed 47.96 g. To the beaker was added 4.826 g of iron pellets. 1. Hematite (iron ore) weighing 75.5 g was placed in a flask whose volume was 53.2 mL. The …
Hematite (iron ore) weighing 70.7 g 70.7 mat{~g} 70.7 g was placed in a flask whose volume was 53.2 m L 53.2 mat{~mL} 53.2 mL. The flask with hematite was then carefully filled with water and weighed.
A mass of iron ore weighing 0.2792g was dissolved in dilute acid and all the iron was converted to Fe2+(aq). The iron II solution required 23.30ml of 0.0194M …
Hematite (iron ore) weighing 70.7 mat{~g} was placed in a flask whose volume was 53.2 mat{~mL}. The flask with hematite was then carefully filled with water and weighed. The hematite and water weighed 109.3 mat{~g}. The density of the water was 0.997 mat{~g} / mat{cm}^{3} . What was the density of the hematite?